Prove that for all positive x, y, and z,
(x+y)^z+(y+z)^x+(z+x)^y > 2.
(In reply to
re: Can get close to 2 - what is missing ? by pcbouhid)
No comment has yet showed that for all positive values of x, y, and z
the expression must exceed 2. Only special cases for the values
of x, y, and z have been considered. Being able to get values close to
(but larger than) 2, does not prove that a value less than or equal to
2 cannot be achieved. We still need to rule out all values of 2 or less
as being values that the expression can take.
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Posted by Richard
on 2005-03-27 20:45:15 |
re(2): Can get close to 2 - what is missing ?
