The problem "Unequally Yoked" looks for all integral solutions for a^b = b^a. But of course, there are a lot of non-integral solutions. If I graph the solution set where a and b are both greater than 0, I get two intersecting curves. Where do the two curves cross?
One solution curve is obviously x=y. For the other, let's suppose a=p
and b=p^q. Since a^b=b^a, then p^(p^q)= (p^q)^p= p^qp, so we have
p^q=pq, or p^(q-1)=q. For this to be an equality, we need
p=q^(1/(q-1)), and we got another solution curve: x=q^(1/(q-1)) and
y=q^(q/(q-1)).
For q=1, this produces the first solution curve.
|
Posted by e.g.
on 2005-04-24 16:41:23 |