Given a triangle ABC, how can you find a point P on AC and a point Q on BC, such that AP=PQ=QB?

N.B. A construction method is sought, and only compass and straightedge are allowed.

Hey, sorry --

Replace my previous step 2 explanation with this one:

2) From the centerpoints P' and Q', strike arcs back along the lines created by segments AC and BC.  The arcs should be of radius P'Q', and where they intersect the lines will be points A' and B'.

Posted by Dan on 2005-05-05 06:48:16