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Just find two! (Posted on 2005-04-27) Difficulty: 4 of 5
Given a triangle ABC, how can you find a point P on AC and a point Q on BC, such that AP=PQ=QB?

N.B. A construction method is sought, and only compass and straightedge are allowed.

See The Solution Submitted by Federico Kereki    
Rating: 4.3333 (3 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: SolutionMcWorter2005-05-14 23:38:39
SolutionSolutionBractals2005-05-14 00:12:51
Just find three for "Just find two!"!McWorter2005-05-11 04:31:06
re: My methodMcWorter2005-05-11 01:06:24
Hints/TipsMy methodFederico Kereki2005-05-10 19:49:55
re(4): Two solutions for one triangle!McWorter2005-05-08 19:22:45
re(3): Two solutions for one triangle!Charlie2005-05-08 03:51:48
re(2): Two solutions for one triangle!McWorter2005-05-08 02:48:19
re: Two solutions for one triangle!Charlie2005-05-07 20:31:19
Two solutions for one triangle!McWorter2005-05-07 01:45:46
oops - different step 2 explanationDan2005-05-05 06:48:16
Another possible solution?Dan2005-05-05 06:37:59
re(2): Non-iterative solutionMcWorter2005-05-04 04:09:14
re: Non-iterative solutionBryan2005-05-03 21:45:36
Non-iterative solutionFederico Kereki2005-05-01 14:41:21
A picture of Bryan's solutionJer2005-04-28 17:38:03
Some Thoughtsre(2): SolutionBryan2005-04-28 15:31:36
Iterative Methodnp_rt2005-04-27 22:40:14
Questionre: SolutionCharlie2005-04-27 20:39:37
SolutionSolutionBryan2005-04-27 20:20:07
Some Thoughtsre(3): May not be possibleOld Original Oskar!2005-04-27 20:19:07
re(2): May not be possibleRichard2005-04-27 20:00:31
re: May not be possibleCharlie2005-04-27 19:49:37
Some ThoughtsNot a solution, but the measured length.Charlie2005-04-27 19:45:53
QuestionMay not be possibleBryan2005-04-27 19:29:18
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