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 Just find two! (Posted on 2005-04-27)
Given a triangle ABC, how can you find a point P on AC and a point Q on BC, such that AP=PQ=QB?

N.B. A construction method is sought, and only compass and straightedge are allowed.

 See The Solution Submitted by Federico Kereki Rating: 4.3333 (3 votes)

 Subject Author Date re: Solution McWorter 2005-05-14 23:38:39 Solution Bractals 2005-05-14 00:12:51 Just find three for "Just find two!"! McWorter 2005-05-11 04:31:06 re: My method McWorter 2005-05-11 01:06:24 My method Federico Kereki 2005-05-10 19:49:55 re(4): Two solutions for one triangle! McWorter 2005-05-08 19:22:45 re(3): Two solutions for one triangle! Charlie 2005-05-08 03:51:48 re(2): Two solutions for one triangle! McWorter 2005-05-08 02:48:19 re: Two solutions for one triangle! Charlie 2005-05-07 20:31:19 Two solutions for one triangle! McWorter 2005-05-07 01:45:46 oops - different step 2 explanation Dan 2005-05-05 06:48:16 Another possible solution? Dan 2005-05-05 06:37:59 re(2): Non-iterative solution McWorter 2005-05-04 04:09:14 re: Non-iterative solution Bryan 2005-05-03 21:45:36 Non-iterative solution Federico Kereki 2005-05-01 14:41:21 A picture of Bryan's solution Jer 2005-04-28 17:38:03 re(2): Solution Bryan 2005-04-28 15:31:36 Iterative Method np_rt 2005-04-27 22:40:14 re: Solution Charlie 2005-04-27 20:39:37 Solution Bryan 2005-04-27 20:20:07 re(3): May not be possible Old Original Oskar! 2005-04-27 20:19:07 re(2): May not be possible Richard 2005-04-27 20:00:31 re: May not be possible Charlie 2005-04-27 19:49:37 Not a solution, but the measured length. Charlie 2005-04-27 19:45:53 May not be possible Bryan 2005-04-27 19:29:18

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