Given a triangle ABC, how can you find a point P on AC and a point Q on BC, such that AP=PQ=QB?

N.B. A construction method is sought, and only compass and straightedge are allowed.

(In reply to Solution by Bractals)

Wonderful!  Even shorter than Kereki's short solution (not shorter verbally, less activity with straightedge and compass)!

By the way, I have just been informed that, with the exception of Bractals and Kereki, we have been snookered by a "coffin" problem, a problem designed to stump "undesirables" without arousing suspicion.

Posted by McWorter on 2005-05-14 23:38:39