Over 2000 numbers are around a circle. Each number is the sum of its left and right neighbors.
Given that one of the numbers is a one, how many numbers (as a minimum) must there be?
(In reply to
re: quick answer by Brad)
I think it could be a multiple of 11 making the minimum 2002.
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Posted by Brad
on 2005-05-27 17:41:59 |