2005 base 10 is not a square. Neither is 2005 base 7 a square (equal 2*7^3+5=691). Is there any base b such that 2005 base b is a square?
(In reply to
re(2): when the base is odd... by pcbouhid)
Your reasoning for odd b appears to be correct to me, if a bit
long-winded. When you got to 16m³+24m²+12m +7 it was already clear that
mod 4 this is congruent to 3, as each term but the last is congruent to
0 mod 4, and 7 is congruent to 3.
Thus I do think that we have solved this problem.
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Posted by Richard
on 2005-05-30 23:37:47 |