Over 2000 numbers are around a circle. Each number is the sum of its left and right neighbors.
Given that one of the numbers is a one, how many numbers (as a minimum) must there be?
(In reply to
re(2): Picky, picky! - I think I got it !! - better !!! by pcbouhid)
I don't understand. "adding two five strings ..." looks like this
(1/2) (-1/2) (-1) (-1/2) (1/2) (1/2) (-1/2) (-1) (-1/2) (1/2)
doesn't it? But the middle string, (1/2) (1/2) (-1/2), violates the sum of neighbors condition. What am I missing?
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Posted by McWorter
on 2005-05-31 03:55:16 |