2005 base 10 is not a square. Neither is 2005 base 7 a square (equal 2*7^3+5=691). Is there any base b such that 2005 base b is a square?

(In reply to Solution by Robby Goetschalckx)

Robby, didn't make a mistake in this sequence :

b^3 = 2*a'^2+2*a'-2

This means b must be even : b = 2*b'

8*b' = 2*a'^2 + 2*a' -2

The left term sholdn't be : 8*b'^3  ?

Posted by pcbouhid on 2005-05-31 19:35:47