The Fibonacci sequence goes F(0)=0, F(1)=1, and for n>1, F(n)=F(n-1)+F(n-2).
Show that for every positive integer m there exists an integer n>0 such that m divides F(n).
(In reply to
Clueless by Steve Herman)
Mathematical induction. "If it is true for m, then it is true for m+1"
That is probably the way this will be solved.
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Posted by Penny
on 2005-06-11 14:18:08 |