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Oodles of Factors (Posted on 2005-07-08) Difficulty: 2 of 5
A. What is the lowest number that has exactly 10 distinct positive factors?

B. Exactly 1,000 distinct positive factors?

C. Exactly 1,000,000 distinct positive factors?

Example: The distinct factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72. Thus 72 has 12 distinct factors.

See The Solution Submitted by Leming    
Rating: 3.1250 (8 votes)

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re: general(ish) sol'n (w/o computer) -correction | Comment 5 of 8 |
(In reply to general(ish) sol'n (w/o computer) by Josh70679)

After reading charlie's solution, i realized i miscounted my primes (*gasp*), and my answer for C is wrong (I left out 37 as a factor).  This adds a wrinkle, as 2^5 = 32 < 37.  That means factoring 1000000 into 10*5^5*2^5 instead of 5^6*2^6 is actually an improvement.  The result using all prime factors is A (below) and the factoring using a 10 is B. 

  • A = 2^4 * 3^4 * 5^4 * 7^4 * 11^4 * 13^4 * 17 * 19 * 23 * 29 * 31 * 37
  • B = 2^9 * 3^4 * 5^4 * 7^4 * 11^4 * 13^4 * 17 * 19 * 23 * 29 * 31

this means A/B = 37/(2^5) > 0, so B is actually better.  I'm pretty sure it's now optimal, but I'm not going to spend the time to prove it ;). 

PS:

  • B = 173,804,636,288,811,640,432,320,000 
  • A = 200,961,610,708,938,459,249,870,000      (thanks Charlie)

  Posted by Josh70679 on 2005-07-08 20:21:29
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