Arthur, Bert and Charles took three exams. In all exams, the first got X points, the second Y points, and the third Z points, X, Y and Z being positive integers such that X>Y>Z.
Summing the three results, Albert got 20 points; Bert, 10; and Charles, 9. Albert was 2nd in Algebra. Who was 2nd in Geometry?
(In reply to
Solution assuming that Albert is Arthur's real name... by Charlie)
The other assumption was that each test had the same number of points, 13.
Without that assumption it could be made to work a number of ways. Two such solutions ...
Test 1 (Alg): B(3), A(2), C(0)
Test 2 (Geo): A(10), C(3), B(0)
Test 3 (Oth): A(8), B(7), C(6)
Where Charles is second in Geo, or ...
Test 1 (Alg): B(3), A(2), C(0)
Test 2 (Geo): A(8), B(1), C(0)
Test 3 (Oth): A(10), C(9), B(6)
where Bert is second in Geo.
re: Solution assuming that Albert is Arthur's real name...
