The goal is to continue a perspective drawing of a floor tiled with congruent square tiles. Specifically, let XY be a horizontal line representing the horizon of the perspective drawing. Let ABCD be one of the square tiles in the foreground, with A nearest the viewer, B on the line XA, D on the line YA, and C the intersection of lines XD and YB. Show how to construct the tile next to ABCD with side BC in common with tile ABCD.

(In reply to My Way by Richard)

Yet a third solution different from mine!  Glad to see that comments don't always end when one solution is found.  (If BD is parallel to XY, then draw CF parallel to XY.)

Posted by McWorter on 2005-08-28 02:19:04