Positive integers a and b are such that (15a+16b) and (16a-15b) are perfect squares. Find the least possible value of the smaller of these two squares.

(In reply to No Subject by xdog)

xdog, SORRY for that, itīs not my intention. I already fixed my comment.

Iīm saying that the first square is 1, because is this that I have found in all books of math, even in recreative publications. Itīs not me who is saying this, the mathematicians are.

Anyway, even if we consider 0 as a square, the two squares you have found are 0 and 481^2, so the least square is 0. Agree? 

Edited on November 16, 2005, 5:49 am

Posted by pcbouhid on 2005-11-15 14:13:21