1. Create every possible two-digit combination.
2. Find their sum.
3. Sum the original three digits.
4. Divide your answer from part 2 by your answer to part 3.

What number do you always get, and why?

Number 2 is ambiguous. Find "their" sum. Are we to find the sum of the digits (see earlier post) or the combinations.

If the latter they will sum to 22(a+b+c) using  a,b,c to represent the digits. Derived from 10a+b; 10b+a; 10a+c; 10c+a; 10b+c; 10c+a.

So the ratio will always be 22 in this interpretation. 22(a+b+c)/(a+b+c)

This answer is probably the one required.