Evaluate this sum in terms of n (the number of terms):
1 2 4 8 16
S = --- + ----- + ----- + ------- + ---------- + .....
2 5 41 3,281 21,523,361
Almost there (not a proof):
Analyzing values for 1-S(n) it can be seen that
1-S(n) = 2^(n+1) / (3^(2^(n+1))-1)
and the sum approaches 1. Now if I could only relate that somehow to the terms of S. The equations are, not surprisingly, very similar.