Evaluate this sum in terms of n (the number of terms):
1 2 4 8 16
S = --- + ----- + ----- + ------- + ---------- + .....
2 5 41 3,281 21,523,361
(In reply to
re: Solution by pcbouhid)
Santa is bringing me new spectacles for Christmas. When I saw "... ", I saw infinite series. Hurry up Santa.
Meantime, adjusting the partial sum formula so that n is the number of terms, I do not see anything amiss with the Bob/Charlie solution
s(n) = 1-2^(n+1)/(3^2^n-1)
which works for the partial sums of the series given or do you have some other series in mind?
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Posted by goFish
on 2005-12-22 10:02:31 |
re(2): Solution
