Replace each letter by a positive rational number such that the following is true. Do it for rationals that can be written in the same denominator that is as small as possible.

O + N + E          =  1
T + W + O          =  2
T + H + R + E + E  =  3
F + O + U + R      =  4
F + I + V + E      =  5
S + I + X          =  6

(In reply to to goFish and dopey - about 0 by pcbouhid)

Well, it was a nice try!  I had already come up with the 6 denominator solution without using 0.

Good puzzle!

An interesting variation would be to allow both positive and negative real numbers (either with or without zero).

 

Posted by dopey915 on 2006-01-02 11:03:34