1. x=the number of even digits, y=the number of odd digits, z=the total number digits.
2. Concatenate to create the number xyz
(a leading zero is ok if x=0)
[Example: 12345678901 has x=5, y=6, z=11 for step 1 and 5611 for step 2]
3. Repeat steps 1 and 2 of this process until your number is unchanged.
What number(s) will the process terminate at?
Will the process always terminate?
Find a 20 digit starting number that terminates in the maximum number of steps (among 20 digit numbers.)
re: Maximum termination- try this
