Setting B = (0,0) and A = (1,0), then C = (0, r) where r is the radius of C2.
Now E is on the intersection of the circles C1: (x-1)^2 + y^2 =1 and C2: x^2 + y^2 =r^2.
Now with a bit of algebra we calculate that the line through CE meets the x-axis at x = 2 + Sqrt(4 - r^2) for r>0.
And trivially gives the solution BG = x -> 4 as r->0.
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Posted by goFish
on 2006-01-14 18:34:08 |