The equation below involves four 5-digits prime numbers:

A + B + C = D

A, B and C are consecutives, B and D are palindromes.

Find A, B, C and D.

(In reply to re: 5 digit primes table by goFish)

Good stuff goFish, I'll take it as read that you worked these all out by hand.

So, 35 possibilities remain for B:

10301,10501,10601,11311,11411,12421,12721,12821,13331,

13831,13931,14341,14741,15451,15551,16061,16361,16561,

16661,17471,17971,18181,18481,19391,19891,19991,30103,

30203,30403,30703,30803,31013,31513,32323,32423

All that remains is for someone to spot which of these is in the middle of three consecutive primes that add up to another one of the five digit pallindromic primes:

Posted by Percy on 2006-01-17 21:26:25