A right triangle PQR, has its hypotenuse, PR, trisected at points A and B. Two lines, QA and QB are then drawn and k is such that QA^2 + QB^2 = (PR^2) * k. Find the value of k.
ante diem VII Id. Mai.
= 9th May
= 5/9
Edited on February 4, 2006, 4:35 am