1. If the number is odd, multiply it by three and add one.
2. If it is even divide it by two.
2a. If the result is still even, continue to divide by two until the result is odd.
3. Continue steps 1 and 2 until you get the same number twice.

[For example starting with 9 -> 28 -> 14 -> 7 which is considered one iteration. The next iteration brings this to 11.]

What number(s) does this process terminate at?
What starting value less than 200 takes the most iterations to terminate?

The program can't be mentioned 'Stupid number trick IV'.

It must be a name which carries more glory.  It deserves it, after having worked so long, up till 20 billion.  And a ceremony/funeral should be held.  Maybe somebody can even do a service in the chatterbox.

I wonder if more people think this is a good idea.