All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Stupid number trick IV (Posted on 2006-01-13)
Take any whole number greater than one.

1. If the number is odd, multiply it by three and add one.
2. If it is even divide it by two.
2a. If the result is still even, continue to divide by two until the result is odd.
3. Continue steps 1 and 2 until you get the same number twice.

[For example starting with 9 -> 28 -> 14 -> 7 which is considered one iteration. The next iteration brings this to 11.]

What number(s) does this process terminate at?
What starting value less than 200 takes the most iterations to terminate?

 See The Solution Submitted by Jer Rating: 4.0000 (4 votes)

 Subject Author Date re: any suggestions? Hugo 2006-02-04 14:53:31 any suggestions? Justin 2006-02-03 23:11:23 *sniff* Hugo 2006-02-03 21:05:03 *sniff* (20 billion and no further) (starts crying) Justin 2006-02-03 19:05:00 14 billion and climbing Justin 2006-01-24 11:04:28 Nothing better to do (Up to 1 billion) Justin 2006-01-21 14:31:03 Sick of re(...), but here you go Justin 2006-01-20 23:45:57 re(6): Going further (520,000,000+) Justin 2006-01-20 13:44:27 Interesting . . . . . . . . Justin 2006-01-20 13:41:34 re(5): Going further (520,000,000+) Hugo 2006-01-20 13:04:51 re(4): Going further (520,000,000+) Justin 2006-01-20 12:58:41 re(3): Going further (520,000,000+) Hugo 2006-01-20 12:54:45 re(2): Going further (520,000,000+) Justin 2006-01-20 09:05:18 re: Going further (520,000,000+) Hugo 2006-01-19 17:24:25 Going further (520,000,000+) Justin 2006-01-19 14:01:40 re: Answer Justin 2006-01-19 13:49:01 re: Collatz Conjecture goFish 2006-01-14 02:20:05 Answer Joe 2006-01-13 20:18:47 Collatz Conjecture The riddler 2006-01-13 19:04:03 A Contribution goFish 2006-01-13 18:52:17 re: interesting property pcbouhid 2006-01-13 16:11:34 interesting property Bob Smith 2006-01-13 15:36:31 Termination Dan 2006-01-13 15:33:28

 Search: Search body:
Forums (0)