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| Trisected Triangle (Posted on 2006-02-03) |
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A right triangle PQR, has its hypotenuse, PR, trisected at points A and B. Two lines, QA and QB are then drawn and k is such that QA^2 + QB^2 = (PR^2) * k. Find the value of k.
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No Solution Yet
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Submitted by Chris, PhD
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Rating: 4.5000 (4 votes)
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easy solution
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 | Comment 11 of 14 | 
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k= 5/9
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Posted by alex
on 2006-03-14 19:49:16 |
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