Determine all integer solutions (x,y,z) for the system of equations
x²z + y²z + 4xy = 40,
x² + y² + xyz = 20
Good job Dej and John! After reading Jer's detailed explanation I had assumed the problem was finished. Reading his post again I see that he left out one possibility:
(x²+y²)=8 (z+2)=5
which, oddly enough, would have provided the other solutions. How unfortunate! Are we now in agreement that those are the only solutions, or is it possible that there may be even more?
Is there any way to know by looking at a problem like this, what the maximum number of solutions could be?
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Posted by tomarken
on 2006-03-30 16:28:17 |
Congrats, and a question
