The product of three consecutive numbers when divided by each of them in turn gives three quotients. The sum of these three quotients is equal to 74.
What are the numbers ?
(In reply to
Solution by fwaff)
If you realize that 5*5 + 5*5 + 5*5 is 75 and the only thing that will change when using 4 and 6 is subtract 1 (see below), you can conclude that way as well.
First of all, if 2 numbers are each d from x, the product of the numbers is (x*x)-(d*d). So (5*5)-(1*1) is 1 less than (5*5)
(x+d)(x-d)=(x*x)-(xd)+(xd)-(d*d)=(x*x)-(d*d)
And (5*5)+(5*5)= ((5+5)*5) = ((4+6)+5) = (4*5) + (6*5).
Adding the two parts together: (5*5)+(5*5)+(5*5) = (4*5) + (6*5) + (4*6) + 1
This might seem more complicated, but it also shows that the product of 3 consecutive numbers is 1 less than the 3 times the middle number squared.
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Posted by Gamer
on 2003-03-12 10:09:59 |