Find the least L.C.M. of 20 natural numbers, not necessarily different, whose sum is 801.
A little juggling and I got an LCM of 80 (probably not the least) by using 1, 80, and eighteen 40's
The principle seems to be to use a lot of copies of a number, then use 1's as needed to make up the 20 numbers.
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Posted by Jer
on 2006-05-19 12:40:24 |