Find the least L.C.M. of 20 natural numbers, not necessarily different, whose sum is 801.
42 is the L.C.M of 20 natural numbers whose sum is 801: ninteen 42s and one 3.
I believe the second lowest L.C.M is 48: sixteen 48s, one 24, and three 3s.
Then followed by 50 as the third lowest L.C.M: thirteen 50s, six 25s, and one 1.
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Posted by Dej Mar
on 2006-05-19 22:03:01 |