We know that f'(x) and f"(x) respectively denote the first derivative and second derivative of a given function f(x) with respect to x.
If P is the inverse function of S, and P'(x)=e
x2; then:
2*S(x)*S'(x) + eS(x)2*S"(x) = ?
I started with P(S(x))=x, so P'(S(x)).S'(x)=1, and then P"(S(x)).(S'(x))²+P'(S(x)).S"(x)=0, but then got stuck... it looks similar to the result, but...
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Posted by e.g.
on 2006-05-28 14:45:07 |