Consider laying out 10 sets of 4 cards plus a turn-up, from a single deck of cards, forming what might appear to be 10 cribbage hands including a different turn-up for each. (Two cards will be left over.)

How could these sets be arranged to maximize the sum of the scores of these hands?

http://en.wikipedia.org/wiki/Cribbage may provide you with some guidance.
Note: Each hand has its own turn-card so a single jack in each hand could be the right jack.

(In reply to Did I just peg out? by Dej Mar)

Well its higher that my best of 196.  I thought it was best to have lots of runs.  Apparently its better to have lots of four of a kinds.  When I post the 'official' solution, I'll include both.

Posted by Jer on 2006-07-19 09:20:56