A= The square of the sum of the number of divisors of each of the divisors of n.

B= The sum of the cubes of the number of divisors of each of the divisors of n

Prove A=B

For example, let's have n=6. Its divisors are 1, 2, 3, and 6. These numbers respectively have 1, 2, 2, and 4 divisors. So A=(1+2+2+4)²=81 and B=1³+2³+2³+4³= 81.

Thanks for catching that. Yes the sum should be from 0 instead of 1. I have corrected the html document. Were you able to follow the proof?

Edited on July 22, 2006, 10:56 pm

Posted by Bractals on 2006-07-22 22:54:55