All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math > Calculus
A Definite Integral Problem (Posted on 2006-08-10) Difficulty: 3 of 5
Consider [x] as the greatest integer function of x and {x}=x–[x].

Evaluate ∫{√x} dx for x=1 to 484.

NOTE: The greatest integer function is defined as a function that produces the "greatest integer less than or equal to the number" operated upon, symbol [x] or sometimes [[x]]. If the number is an integer, use that integer. If the number is not an integer, use the next smaller integer.

See The Solution Submitted by K Sengupta    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution | Comment 1 of 5

This should be equivalent to the integral of sqrt(x)dx from 1 to 484 less the sum 1*3 + 2*5 + 3*7 + 4*9 + ... + 21*43.

The integral evaluates to (2/3)(484)^3/2 - (2/3)*(1)^3/2 = 7098 while the sum can be broken into the sum of 2n^2 and n from n=1 to 21 or 2(7*11*43) + (11*21) = 6853

The difference between the integral and the sum is:

7098 - 6853 = 245


  Posted by Eric on 2006-08-10 13:37:48
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information