Last month, the Trent family moved next to the Newley's. One fine afternoon, Mrs. Trent called on Mrs. Newley to get acquainted with the Newley family. In the course of the conversation, when Mrs. Trent queried Mrs. Newley about the age of her daughter Jackie, Mrs. Newley responded cryptically, “When she was born, I was precisely five times the age of her brother Tony at that time. Six years from now, Jackie will be one third of the age which I will attain at that time.”

At this point, Mrs. Trent requested some additional information when Mrs. Newley replied, ”The sum of squares of the digits of my husband’s present age in years, is two more than my current age. Presently, my age is nine years more than that of Tony’s father (my husband) when Tony was born”.

Determine the current ages of Mr. Newley, Mrs. Newley and their two children from the above statements.

(In reply to solution by Charlie)

I had found the same solution, though I had meandered to the solution on a slightly different route.

Mr. Newley = 45; Mrs. Newley = 39; Tony = 15; Jackie = 9

“When she was born, I was precisely five times the age of her brother Tony at that time."  Mrs. Newley = 30 & Tony = 6

"Six years from now, Jackie will be one third of the age which I will attain at that time.”  Mrs. Newley = 45 & Jackie = 15

”The sum of squares of the digits of my husband’s present age in years, is two more than my current age."  4²+5² = 39 + 2

"Presently, my age is nine years more than that of Tony’s father (my husband) when Tony was born”  45 - 15 = 39 - 9 

Posted by Dej Mar on 2006-08-31 19:51:53