All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
A Sequential Reduction Problem (Posted on 2006-09-09) Difficulty: 3 of 5
A certain factory had decided to sequentially reduce its annual expenditure on a specified raw material over a period of three years, starting from 2003. The proposed sequential annual reductions were respectively P%, Q% and R%; where P< Q< R< 100, and the three numbers are positive integers in geometric progression.

For example, if the annual expenditure for 2002 was 1000 units and the sequential reductions for the years 2003 to 2005 were respectively 10%, 10% and 20%, then the amount spent on the raw material during 2005 would have been 1000*.9*.9*.8 = 648 units.

Thus, the amounts spent during 2003, 2004 and 2005 were respectively $L, $M, and $N; the three numbers were positive integers in arithmetic progression.

Determine P, Q and R.

See The Solution Submitted by K Sengupta    
Rating: 3.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Question No Subject | Comment 3 of 4 |

A geometric progression is in the form ..., arx, arx+1, arx+2, arx+3, arx+4,...; such that r not = 0 and x is an interger >= 0.  How is the sequence -- 10%, 10%, 20% -- a geometric progression?

 

 

Edited on September 9, 2006, 9:39 pm
  Posted by Dej Mar on 2006-09-09 21:37:19

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information