All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
A rational number problem (Posted on 2006-10-02) Difficulty: 3 of 5
Determine the total number of rational numbers of the form m/n, where m and n are positive integers such that:

(A) m/n lies in the interval (0, 1); and

(B) m and n are relatively prime; and

(C) mn = 25!

NOTE: "!" denotes the factorial symbol, where n! = 1*2*3*......*(n-1)*n

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
The rest | Comment 10 of 12 |
The rest(call it  R) are all the factors that must be lumped together to satisfy the condition of relatively prime. They are: All the even numbers, three and all its multiples (since 3 divides 6), five and all its multiples (since 5 divides 10), seven and its multiples (since 7 divides 14), 11 and its mutiple (since 11 divides 22). Thus the only factors of 25! that can be used to form m/n and satisfy the relatively prime condition are 23,19,17,13, and R. To see that this is true, try to move any factor in R from n to m.
    Fogey

  Posted by Larry Settle on 2006-10-06 22:45:03
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information