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Some other kind of root extraction (Posted on 2006-11-07) Difficulty: 4 of 5
Let's call a real-valued continuous function an n-th identity root when it generates the identity function after exactly n compositions with itself. For example f(x)=-x is a 2nd identity root because f(f(x))=x.

1. The function f(x)=1-1/x is a 3rd identity root. Unfortunately it is undefined at x=0. Are there identity roots for n>2 which are defined for all real numbers?

2. For a given real number c and n>1, give an example of an n-th identity root which is defined for all real numbers except c. How many such roots exist?

See The Solution Submitted by JLo    
Rating: 4.2500 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: There's still something to find... | Comment 4 of 10 |
(In reply to There's still something to find... by JLo)

how nice are we talking?

tan(arctan(x-c+tan(pi/2-pi/n))+pi/n)

seems to do the trick, though it seems like it isn't really using a circle and dealing with the c part seems very ugly...

  Posted by Joel on 2006-11-08 19:26:41

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