ΔABC is equilateral. Point D lies on line BC such that C lies between B and D. Point E lies on side AC such that ED bisects angle ADC. Point F lies on side AB such that FE and BC are parallel. Point G lies on side BC such that GF=EF.

Prove that angle DAC equals twice angle GAC.

Try as I might, I can't seem to get past the <AGE = 30 in the posted solution.

Posted by Kenny M on 2006-11-28 19:44:51