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More Harmonic Integers (Posted on 2007-03-12) Difficulty: 2 of 5
Determine three positive integers x, y and z in harmonic sequence such that x<y<z, xy=z, and (x, y, z-72) are in arithmetic sequence.

See The Solution Submitted by K Sengupta    
Rating: 3.5000 (2 votes)

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Solution spoiler | Comment 1 of 3

x=7

y=13

z=91

expressing in x we get  x  2*x-1  2*x^2-x-72

as members of arithm. progression.

 solving - we get the values as above


  Posted by Ady TZIDON on 2007-03-12 08:26:48
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