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Polynomial Puzzle (Posted on 2007-03-16)

Let p(x)=x^4+ax^3+bx^2+cx+d, where a, b, c, and d are constants.

If p(1)=-9, p(2)=-18, and p(3)=-27, find the value of ¼(p(10)+p(-6)).

See The Solution Submitted by Dennis

Rating: 4.0000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

re(2): If there's only one answer...

| Comment 4 of 7 |

(In reply to re: If there's only one answer... by Gamer)

Me be dumb, dumb, dumb...!!! I just plain forgot that 10 and -6 weren't roots of the added polynomial!

Posted by Federico Kereki on 2007-03-16 17:02:34

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