Two points, A and B, are on the Cartesian plane at (-1,4) and (9,6).
A. What point on the x-axis is equidistant from each of these two points?
B. What point on the y-axis is equidistant from these two points?
(In reply to
pretty easy by DuCk)
The segment connecting the points has slope = 1/5
The perpendicular bisector of the segement has slope -5 and passes through the point (4,5). Its equation is y=-5x+25
(Recall every point on the perp. bisector is equidistant from the endpoints)
This line has y-int.=25 and x-int=5
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Posted by Jer
on 2003-03-28 07:33:59 |
re: pretty easy :easier
