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A problem to end all shift-a-digit problems (Posted on 2007-03-26)

Prove that there exists no natural number such that shifting its first digit to the end, multiplies it by 5, 6, or 8.

See The Solution Submitted by e.g.

Rating: 4.0000 (1 votes)

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re: Something of a solution (one example)

| Comment 2 of 3 |

(In reply to Something of a solution. by Leming)

61₂₉ = 175₁₀
16₂₉= 35₁₀
61₂₉ / 5 = 16₂₉

71₄₁ = 288₁₀
17₄₁= 48₁₀
71₄₁ / 6 = 17₄₁

91₇₁ = 640₁₀
19₇₁= 80₁₀
91₇₁ / 8 = 19₇₁

Edited on March 27, 2007, 1:14 am

Posted by Dej Mar on 2007-03-27 01:03:34

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