The cryptarithm FLOOBLE + PUZZLE = PERPLEX has no solutions. But if the word 'PUZZLE' is included twice, then there is a solution.
How many more times can the word 'PUZZLE' appear in the addition and the cryptarithm still have a solution?
(In reply to
re: answer by Charlie)
True.
Indeed M=5 does not possess any solution to the given
alphametic equation.
The said anomaly occurred due to a typographical error and the foregoing lacunae is sincerely regretted.
Consequently, I confirm having suitably amended my original post.