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| Always Divisible (Posted on 2007-05-20) |
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Prove that for every integer x, there is an integer y such that (y^2-2)/(x^4+1) is an integer.
Solution
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 | Comment 2 of 3 | 
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This y works: y=x^3-x y^2 - 2 = x^6 - 2x^4 + x^2 - 2 = (x^4 + 1)*(x^2 - 2) -- Joel
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Posted by Joel
on 2007-05-21 02:58:29 |
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