10% of 10=1,
20% 0f 20=4,
30% of 30=9,
40% of 40=16,........
90% 0f 90=81,
100% 0f 100=100,.....

Is it possible to create a similar series that gives us triangular numbers as the result?

Summarizing, there are precisely 10 valid series satisfying the
conditions of the problem, ignoring the cases:(a,b) = (50n, n+1)
and (50(n+1), n)

Posted by K Sengupta on 2007-06-28 11:23:27