All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Perfect Squares (Posted on 2003-04-05) Difficulty: 5 of 5
Show that the numbers of the form:

444444....4444888888....8889

[Where there are 'k' Fours, '(k-1)' Eights and 'Exactly One' 9],

are always perfect squares.

(For example the sequence of numbers: 49, 4489, 444889, ....etc. and so on are always perfect squares).

See The Solution Submitted by Ravi Raja    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution(simple) | Comment 9 of 10 |
The number 44444..48888..89 can be written as:
N=1+4444...4888..8=1+8(1+10+...+10^(k-1))+4*10^k*(1+10+...+10^(k-1))
N=1+(4*10^k+8)*((1+10+...+10^(k-1))
N=1+4*(10^k+2)*(10^k-1)/9 (Sum of k terms of GP)
N=1+(4/9)*(10^(2k)-2+10^k)
N=1/9*(9+4*10^2k-8+4*10^k)
N=1/9*(1+4*10^2k+4*10^k)
N=((2*10^k+1)/3)²
So, N is a perfect square.

  Posted by Praneeth Yalavarthi on 2007-07-10 13:06:21
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information