In the following grid, the numbers from 1 to 6 occur only once per row, per column, or per colored rectangle. Given the relations between numbers and a single number to get you started, can you complete the grid?
| | | | | | | | | | | | | |
| | > | | > | | | | < | | < | | | |
| v | | ^ | | v | | ^ | | ^ | | ^ | | |
| | < | | > | | | | > | | < | | | |
| | | | | | | | | | | | | |
| | < | | > | | | | < | | > | 3 | | |
| v | | v | | ^ | | ^ | | v | | ^ | | |
| | > | | < | | | | > | | < | | | |
| | | | | | | | | | | | | |
| | < | | < | | | | < | | > | | | |
| ^ | | v | | ^ | | v | | v | | ^ | | |
| | > | | < | | | | < | | > | | | |
| | | | | | | | | | | | | |
I played "Find the Ones" and:
- there's one in the first row, 4th column
- hence there's one in the 5th row, 6th column (the other possibility in
that rectangle would be the 6th row, 4th column, but that isn't allowed)
- hence there's one in the 6th row, 2nd column
- hence there's one in the 3rd row, 3rd column
- hence there's one in the 2nd row, 1st column
- the last one is in the 5th row, 5th column.
Now for the twos:
- there's one in the 3rd row, 4th column
- there's one in the 1st row, 5th column
- hence the one in the 6th column is in the 6th row
- hence there's one in the 5th row, 1st column
- hence there's one in the 4th row, 2nd column
- hence the one in the 3rd column is in the 2nd row
The threes (and let's write a little less):
- 6th row, 4th column
- 2nd row, 5th column
- 1st row, 3rd column
- 4th row, 1st column
- 5th row, 2nd column
The fours:
- 1st row, 2nd column
- 2nd row, 4th column
- 6th row, 5th column
- 5th row, 3rd column
- 3rd row, 1st column
- 4th row, 6th column
The fives:
- 1st row, 6th column
- 5th row, 4th column
- 3rd row, 5th column
- 4th row, 3rd column
- 6th row, 1st column
- 2nd row, 2nd column
And the sixes go in the remaining cells! Whew!!
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Posted by e.g.
on 2007-07-15 15:38:29 |
All worked out!
