Determine all possible real pairs (p, q) satisfying the following system of equations:
4p(p+q-5) = 3q
q(p+q-4) = 16p
Given 4p(p+q-5)=3q ---(1), q(p+q-4)=16p ---(2)
Multiply (1) and (2) and after further simplification
4*p*q*((p+q)²-9*(p+q)+8)=0.
So, solutions are p=0 or q=0 or p+q=8 or p+q=1
Substitue these eq(1) to get these (p,q) pairs
(0,0),(-3/13,16/13) and (8/5,32/5)
Edited on July 19, 2007, 10:16 am
Edited on July 20, 2007, 6:16 am