Determine all possible positive real p satisfying 18[p] + 35{p} = 673, where [y] denotes the greatest integer ≤ y and {y} = y - [y]
Hi!
I start with replace {p} = p-[p] and so I find a new equation
35p=673+17[p].
Because the right expresion is a integer and positive number the left is the same and so 35p = k where k is a positive and integer number.
So I replace p with k/35
From the new relation k = 673+17[k/35] I find that
[k/35] = (k-673)/17 and after this I use the properties of the [y] function ( y-1<[y]<=y) and I find two inequalities.
k/35 - 1 < (k-673)/17 <= k/35.
After resolve this I found
1275<k<=1308 but [k/35] can be only 36 or 37 so the answer is
(1) p = 1285/35
(2) p=1302/35
Calculus.......
