444444....4444888888....8889

[Where there are 'k' Fours, '(k-1)' Eights and 'Exactly One' 9],

are always perfect squares.

(For example the sequence of numbers: 49, 4489, 444889, ....etc. and so on are always perfect squares).

Yes Gamer, in "one of the methods" by the help of which the problem can be solved this sequence,".... the sum of (10^x)+(10^x-1)+...+(10^1))...." that you have posted in your comment is required. I meant that of courlse that will help.

Posted by Ravi Raja on 2003-04-07 04:29:26